Câu trả lời tốt nhất
Ka = 5.10^-6 —> Kb = 2.10^-9
NO2- + H2O ↔ HNO2 + OH-
0,001
x…………………..x………..x
0,001-x…………..x………..x
Kb = x.x/(0,001 – x) = 2.10^-9
—> x = 1,4132.10^-6
—> pOH = 5,85 —> pH = 8,15
×
Ka = 5.10^-6 —> Kb = 2.10^-9
NO2- + H2O ↔ HNO2 + OH-
0,001
x…………………..x………..x
0,001-x…………..x………..x
Kb = x.x/(0,001 – x) = 2.10^-9
—> x = 1,4132.10^-6
—> pOH = 5,85 —> pH = 8,15